What are the solutions to the equation 2x^2-56=-9x ?

The solutions to the equation 2x^2-56=-9x are x= 7/2 ,x=-8

Find the zeros of 2x^2-56=-9x

The zeros of 2x^2-56=-9x are x= 7/2 ,x=-8

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2 x^{2} - 56 = - 9 x

x = \frac{7}{2}, x = - 8

Solution steps

2 x^{2} - 56 = - 9 x

Move

9 x

to the left side

2 x^{2} - 56 + 9 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} + 9 x - 56 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 2 ( - 56 )}{2 \cdot 2}

9^{2} - 4 \cdot 2 (- 56) = 23

x_{1, 2} = \frac{- 9 \pm 23}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 9 + 23}{2 \cdot 2}, x_{2} = \frac{- 9 - 23}{2 \cdot 2}

x = \frac{- 9 + 23}{2 \cdot 2} : \frac{7}{2}

x = \frac{- 9 - 23}{2 \cdot 2} : - 8

The solutions to the quadratic equation are:

x = \frac{7}{2}, x = - 8

(9 - y)^{2} + y^{2} = 53

m^{2} - 1.04 = 1.16

8 x^{2} + x - 9 = 0

- 2 x^{2} + 3 x + 4 = 0

48 = (2 x + 6) (2 x + 4)

What are the solutions to the equation 2x^2-56=-9x ?
The solutions to the equation 2x^2-56=-9x are x= 7/2 ,x=-8
Find the zeros of 2x^2-56=-9x
The zeros of 2x^2-56=-9x are x= 7/2 ,x=-8