What are the solutions to the equation (3x+4)^2=0 ?

The solutions to the equation (3x+4)^2=0 are x=-4/3

Find the zeros of (3x+4)^2=0

The zeros of (3x+4)^2=0 are x=-4/3

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(3 x + 4)^{2} = 0

x = - \frac{4}{3}

Decimal Notation

x = - 1.33333 \dots

Solution steps

(3 x + 4)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

3 x + 4 = 0 : x = - \frac{4}{3}

The solution to the quadratic equation is:

x = - \frac{4}{3}

x, (x + y)^{2} y = 9

x^{2} + 2 = 3 x^{2} - 16

3 x (x - 2) = 2 (x - 2)

3 x^{2} + 6 x = 0

3 x (x - 3) = 7

What are the solutions to the equation (3x+4)^2=0 ?
The solutions to the equation (3x+4)^2=0 are x=-4/3
Find the zeros of (3x+4)^2=0
The zeros of (3x+4)^2=0 are x=-4/3