What are the solutions to the equation 6a^2+2a-113=-9 ?

The solutions to the equation 6a^2+2a-113=-9 are a=4,a=-13/3

Find the zeros of 6a^2+2a-113=-9

The zeros of 6a^2+2a-113=-9 are a=4,a=-13/3

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6 a^{2} + 2 a - 113 = - 9

a = 4, a = - \frac{13}{3}

Solution steps

6 a^{2} + 2 a - 113 = - 9

Move

9

to the left side

6 a^{2} + 2 a - 104 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 6 ( - 104 )}{2 \cdot 6}

2^{2} - 4 \cdot 6 (- 104) = 50

a_{1, 2} = \frac{- 2 \pm 50}{2 \cdot 6}

Separate the solutions

a_{1} = \frac{- 2 + 50}{2 \cdot 6}, a_{2} = \frac{- 2 - 50}{2 \cdot 6}

a = \frac{- 2 + 50}{2 \cdot 6} : 4

a = \frac{- 2 - 50}{2 \cdot 6} : - \frac{13}{3}

The solutions to the quadratic equation are:

a = 4, a = - \frac{13}{3}

x \frac{4 x - 3}{5} - \frac{2 x - 3}{2} = - 2

9 x (x + 1) 2 - 4 = 0

p^{2} - 2 p - 48 = 0

x^{2} - 5 x - 1 = - 5

r, A = π r h + π r^{2}

What are the solutions to the equation 6a^2+2a-113=-9 ?
The solutions to the equation 6a^2+2a-113=-9 are a=4,a=-13/3
Find the zeros of 6a^2+2a-113=-9
The zeros of 6a^2+2a-113=-9 are a=4,a=-13/3