What are the solutions to the equation x^2-1/2 x-3=0 ?

The solutions to the equation x^2-1/2 x-3=0 are x=2,x=-3/2

Find the zeros of x^2-1/2 x-3=0

The zeros of x^2-1/2 x-3=0 are x=2,x=-3/2

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x^{2} - \frac{1}{2} x - 3 = 0

x = 2, x = - \frac{3}{2}

Solution steps

x^{2} - \frac{1}{2} x - 3 = 0

Multiply both sides by

2

2 x^{2} - x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 6 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 6) = 7

x_{1, 2} = \frac{- ( - 1 ) \pm 7}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 7}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 7}{2 \cdot 2}

x = \frac{- ( - 1 ) + 7}{2 \cdot 2} : 2

x = \frac{- ( - 1 ) - 7}{2 \cdot 2} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = 2, x = - \frac{3}{2}

\frac{4}{9} - \frac{d ^{2}}{25} = 0

s^{2} = - 1

x, 9 x^{2} + 12 x y + 4 y^{2} - 48 x - 32 y + 64 = 0

x^{2} - 8 = - 2 x

\frac{t ^{2}}{330} - \frac{t}{5} + 24 = 0

What are the solutions to the equation x^2-1/2 x-3=0 ?
The solutions to the equation x^2-1/2 x-3=0 are x=2,x=-3/2
Find the zeros of x^2-1/2 x-3=0
The zeros of x^2-1/2 x-3=0 are x=2,x=-3/2