What are the solutions to the equation 4w^2+25=-20w ?

The solutions to the equation 4w^2+25=-20w are w=-5/2

Find the zeros of 4w^2+25=-20w

The zeros of 4w^2+25=-20w are w=-5/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 w^{2} + 25 = - 20 w

w = - \frac{5}{2}

Solution steps

4 w^{2} + 25 = - 20 w

Move

20 w

to the left side

4 w^{2} + 25 + 20 w = 0

Write in the standard form

a x^{2} + b x + c = 0

4 w^{2} + 20 w + 25 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 4 \cdot 25}{2 \cdot 4}

2 0^{2} - 4 \cdot 4 \cdot 25 = 0

w_{1, 2} = \frac{- 20 \pm 0}{2 \cdot 4}

w = \frac{- 20}{2 \cdot 4}

\frac{- 20}{2 \cdot 4} = - \frac{5}{2}

w = - \frac{5}{2}

The solution to the quadratic equation is:

w = - \frac{5}{2}

0 = 3 x^{2} + 10 x - 8

(x + 5)^{2} = - 16

(6.4 \cdot 1 0^{- 7} - x) (11.4 \cdot 1 0^{- 7} - x) = 4.1 \cdot 1 0^{- 13}

1 - 8 m^{2} = - 7

59 = q^{2} - 12 q + 41

What are the solutions to the equation 4w^2+25=-20w ?
The solutions to the equation 4w^2+25=-20w are w=-5/2
Find the zeros of 4w^2+25=-20w
The zeros of 4w^2+25=-20w are w=-5/2