What are the solutions to the equation x(x+10)+20=-5 ?

The solutions to the equation x(x+10)+20=-5 are x=-5

Find the zeros of x(x+10)+20=-5

The zeros of x(x+10)+20=-5 are x=-5

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x (x + 10) + 20 = - 5

x = - 5

Solution steps

x (x + 10) + 20 = - 5

Expand

x (x + 10) + 20 : x^{2} + 10 x + 20

x^{2} + 10 x + 20 = - 5

Move

5

to the left side

x^{2} + 10 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 25 = 0

x_{1, 2} = \frac{- 10 \pm 0}{2 \cdot 1}

x = \frac{- 10}{2 \cdot 1}

\frac{- 10}{2 \cdot 1} = - 5

x = - 5

The solution to the quadratic equation is:

x = - 5

10 x^{2} - 60 x = 0

6 x^{2} - 13 x = 5

x, 9 x^{2} - 4 y^{2} = 0

c, y^{2} (x) = c (x + \frac{c}{4})

\frac{( x - 3 ) ^{2}}{16} - \frac{( x - 4 ) ^{2}}{9} = 1

What are the solutions to the equation x(x+10)+20=-5 ?
The solutions to the equation x(x+10)+20=-5 are x=-5
Find the zeros of x(x+10)+20=-5
The zeros of x(x+10)+20=-5 are x=-5