What are the solutions to the equation a^2+2=2a ?

The solutions to the equation a^2+2=2a are a=1+i,a=1-i

Find the zeros of a^2+2=2a

The zeros of a^2+2=2a are a=1+i,a=1-i

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a^{2} + 2 = 2 a

a = 1 + i, a = 1 - i

Solution steps

a^{2} + 2 = 2 a

Move

2 a

to the left side

a^{2} + 2 - 2 a = 0

Write in the standard form

a x^{2} + b x + c = 0

a^{2} - 2 a + 2 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 2 : 2 i

a_{1, 2} = \frac{- ( - 2 ) \pm 2 i}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 2 ) + 2 i}{2 \cdot 1}, a_{2} = \frac{- ( - 2 ) - 2 i}{2 \cdot 1}

a = \frac{- ( - 2 ) + 2 i}{2 \cdot 1} : 1 + i

a = \frac{- ( - 2 ) - 2 i}{2 \cdot 1} : 1 - i

The solutions to the quadratic equation are:

a = 1 + i, a = 1 - i

- 0.1 x^{2} + 250 = 0.6 x^{2} + 0.2 x + 100

t^{2} - 10 t + 10 = 0

x, 4 x^{2} y^{2} + 2 x y - 12 = 0

(x + 4)^{2} - (2 x + 3) (x - 2) = 42

6 (x + 1) - (4 - x) (x + 1) = 6 (4 - x)

What are the solutions to the equation a^2+2=2a ?
The solutions to the equation a^2+2=2a are a=1+i,a=1-i
Find the zeros of a^2+2=2a
The zeros of a^2+2=2a are a=1+i,a=1-i