What are the solutions to the equation (x^2+16)=0 ?

The solutions to the equation (x^2+16)=0 are x=4i,x=-4i

Find the zeros of (x^2+16)=0

The zeros of (x^2+16)=0 are x=4i,x=-4i

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(x^{2} + 16) = 0

x = 4 i, x = - 4 i

Solution steps

(x^{2} + 16) = 0

x^{2} + 16 = 0

Move

16

to the right side

x^{2} = - 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 16, x = - - 16

- 16 = 4 i

- - 16 = - 4 i

x = 4 i, x = - 4 i

(6 x) (x - 6) = 0

- x^{2} - 10 x = 0

45 x^{2} - 78 x - 63 = 0

4 - 4 x^{2} = - 296

(u - 3)^{2} - 72 = 0

What are the solutions to the equation (x^2+16)=0 ?
The solutions to the equation (x^2+16)=0 are x=4i,x=-4i
Find the zeros of (x^2+16)=0
The zeros of (x^2+16)=0 are x=4i,x=-4i