What are the solutions to the equation 2x^2-x=-8 ?

The solutions to the equation 2x^2-x=-8 are x= 1/4+i(3sqrt(7))/4 ,x= 1/4-i(3sqrt(7))/4

Find the zeros of 2x^2-x=-8

The zeros of 2x^2-x=-8 are x= 1/4+i(3sqrt(7))/4 ,x= 1/4-i(3sqrt(7))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} - x = - 8

x = \frac{1}{4} + i \frac{3 7}{4}, x = \frac{1}{4} - i \frac{3 7}{4}

Solution steps

2 x^{2} - x = - 8

Move

8

to the left side

2 x^{2} - x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 \cdot 8}{2 \cdot 2}

Simplify

(- 1)^{2} - 4 \cdot 2 \cdot 8 : 37 i

x_{1, 2} = \frac{- ( - 1 ) \pm 3 7 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 3 7 i}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 3 7 i}{2 \cdot 2}

x = \frac{- ( - 1 ) + 3 7 i}{2 \cdot 2} : \frac{1}{4} + i \frac{3 7}{4}

x = \frac{- ( - 1 ) - 3 7 i}{2 \cdot 2} : \frac{1}{4} - i \frac{3 7}{4}

The solutions to the quadratic equation are:

x = \frac{1}{4} + i \frac{3 7}{4}, x = \frac{1}{4} - i \frac{3 7}{4}

(7 - 3 x) (x + 2) = 4

x^{2} - 6 x - 7 = 0

15000 = - 0.5 x^{2} + 40 x - 300

\frac{x ^{2}}{3} = \frac{11}{6} x + 1

(k + 2) x^{2} + 5 x - 3 = 0

What are the solutions to the equation 2x^2-x=-8 ?
The solutions to the equation 2x^2-x=-8 are x= 1/4+i(3sqrt(7))/4 ,x= 1/4-i(3sqrt(7))/4
Find the zeros of 2x^2-x=-8
The zeros of 2x^2-x=-8 are x= 1/4+i(3sqrt(7))/4 ,x= 1/4-i(3sqrt(7))/4