What are the solutions to the equation 6t^2-13t=15 ?

The solutions to the equation 6t^2-13t=15 are t=3,t=-5/6

Find the zeros of 6t^2-13t=15

The zeros of 6t^2-13t=15 are t=3,t=-5/6

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6 t^{2} - 13 t = 15

t = 3, t = - \frac{5}{6}

Decimal Notation

t = 3, t = - 0.83333 \dots

Solution steps

6 t^{2} - 13 t = 15

Move

15

to the left side

6 t^{2} - 13 t - 15 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 6 ( - 15 )}{2 \cdot 6}

(- 13)^{2} - 4 \cdot 6 (- 15) = 23

t_{1, 2} = \frac{- ( - 13 ) \pm 23}{2 \cdot 6}

Separate the solutions

t_{1} = \frac{- ( - 13 ) + 23}{2 \cdot 6}, t_{2} = \frac{- ( - 13 ) - 23}{2 \cdot 6}

t = \frac{- ( - 13 ) + 23}{2 \cdot 6} : 3

t = \frac{- ( - 13 ) - 23}{2 \cdot 6} : - \frac{5}{6}

The solutions to the quadratic equation are:

t = 3, t = - \frac{5}{6}

x^{2} + (2 - 2 e^{2}) x + 2 = 0

v, p = \frac{m v ^{2}}{2}

2 x^{2} - 8 x + 16 = 38

x^{2} - 21 x + 104 = 0

y, x = \frac{1}{2} y^{2} + \frac{1}{4}

What are the solutions to the equation 6t^2-13t=15 ?
The solutions to the equation 6t^2-13t=15 are t=3,t=-5/6
Find the zeros of 6t^2-13t=15
The zeros of 6t^2-13t=15 are t=3,t=-5/6