What are the solutions to the equation x^2-3x=-5/4 ?

The solutions to the equation x^2-3x=-5/4 are x= 5/2 ,x= 1/2

Find the zeros of x^2-3x=-5/4

The zeros of x^2-3x=-5/4 are x= 5/2 ,x= 1/2

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x^{2} - 3 x = - \frac{5}{4}

x = \frac{5}{2}, x = \frac{1}{2}

Decimal Notation

x = 2.5, x = 0.5

Solution steps

x^{2} - 3 x = - \frac{5}{4}

Multiply both sides by

4

4 x^{2} - 12 x = - 5

Move

5

to the left side

4 x^{2} - 12 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 \cdot 5}{2 \cdot 4}

(- 12)^{2} - 4 \cdot 4 \cdot 5 = 8

x_{1, 2} = \frac{- ( - 12 ) \pm 8}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 8}{2 \cdot 4}, x_{2} = \frac{- ( - 12 ) - 8}{2 \cdot 4}

x = \frac{- ( - 12 ) + 8}{2 \cdot 4} : \frac{5}{2}

x = \frac{- ( - 12 ) - 8}{2 \cdot 4} : \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = \frac{1}{2}

x^{2} - 9 x + 11 x + 12 = 180

2 x + 3 = - x^{2}

0.5 (x - 1)^{2} - 0.25 (x + 1)^{2} = 4 - x

t, s = - 16 t^{2} + 108 t

x^{2} + 28 x - 128 = 0

What are the solutions to the equation x^2-3x=-5/4 ?
The solutions to the equation x^2-3x=-5/4 are x= 5/2 ,x= 1/2
Find the zeros of x^2-3x=-5/4
The zeros of x^2-3x=-5/4 are x= 5/2 ,x= 1/2