What are the solutions to the equation 2x^2+5x-58=0 ?

The solutions to the equation 2x^2+5x-58=0 are x=(-5+sqrt(489))/4 ,x=(-5-sqrt(489))/4

Find the zeros of 2x^2+5x-58=0

The zeros of 2x^2+5x-58=0 are x=(-5+sqrt(489))/4 ,x=(-5-sqrt(489))/4

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2 x^{2} + 5 x - 58 = 0

x = \frac{- 5 + 489}{4}, x = \frac{- 5 - 489}{4}

Decimal Notation

x = 4.27833 \dots, x = - 6.77833 \dots

Solution steps

2 x^{2} + 5 x - 58 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 ( - 58 )}{2 \cdot 2}

5^{2} - 4 \cdot 2 (- 58) = 489

x_{1, 2} = \frac{- 5 \pm 489}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 5 + 489}{2 \cdot 2}, x_{2} = \frac{- 5 - 489}{2 \cdot 2}

x = \frac{- 5 + 489}{2 \cdot 2} : \frac{- 5 + 489}{4}

x = \frac{- 5 - 489}{2 \cdot 2} : \frac{- 5 - 489}{4}

The solutions to the quadratic equation are:

x = \frac{- 5 + 489}{4}, x = \frac{- 5 - 489}{4}

- 8 x^{2} + 3 x^{2} + 3 x - 1 = - 9 x - 8 - 6 x - 7 x^{2} + 7

a, 2 b y - 3 a y = 4 b^{2} - 9 a^{2}

(x - 5)^{2} - 10 = 0

5 (a - 2)^{2} + 3 (a + 1) = 25

- 16 t^{2} + 32 t = 0

What are the solutions to the equation 2x^2+5x-58=0 ?
The solutions to the equation 2x^2+5x-58=0 are x=(-5+sqrt(489))/4 ,x=(-5-sqrt(489))/4
Find the zeros of 2x^2+5x-58=0
The zeros of 2x^2+5x-58=0 are x=(-5+sqrt(489))/4 ,x=(-5-sqrt(489))/4