What are the solutions to the equation -4x^2-6x+1=0 ?

The solutions to the equation -4x^2-6x+1=0 are x=-(3+sqrt(13))/4 ,x=(sqrt(13)-3)/4

Find the zeros of -4x^2-6x+1=0

The zeros of -4x^2-6x+1=0 are x=-(3+sqrt(13))/4 ,x=(sqrt(13)-3)/4

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- 4 x^{2} - 6 x + 1 = 0

x = - \frac{3 + 13}{4}, x = \frac{13 - 3}{4}

Decimal Notation

x = - 1.65138 \dots, x = 0.15138 \dots

Solution steps

- 4 x^{2} - 6 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( - 4 ) \cdot 1}{2 ( - 4 )}

(- 6)^{2} - 4 (- 4) \cdot 1 = 213

x_{1, 2} = \frac{- ( - 6 ) \pm 2 13}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 13}{2 ( - 4 )}, x_{2} = \frac{- ( - 6 ) - 2 13}{2 ( - 4 )}

x = \frac{- ( - 6 ) + 2 13}{2 ( - 4 )} : - \frac{3 + 13}{4}

x = \frac{- ( - 6 ) - 2 13}{2 ( - 4 )} : \frac{13 - 3}{4}

The solutions to the quadratic equation are:

x = - \frac{3 + 13}{4}, x = \frac{13 - 3}{4}

(5 x - 9)^{2} = 1296

- 5 x^{2} - 87 x - 391 = 3 x - 63 x - 6

x, x^{2} + y^{2} - 4 x + 10 y + 29 = 0

2 x^{2} = - x + 3

x^{2} + 14 x + 49 = 0

What are the solutions to the equation -4x^2-6x+1=0 ?
The solutions to the equation -4x^2-6x+1=0 are x=-(3+sqrt(13))/4 ,x=(sqrt(13)-3)/4
Find the zeros of -4x^2-6x+1=0
The zeros of -4x^2-6x+1=0 are x=-(3+sqrt(13))/4 ,x=(sqrt(13)-3)/4