What are the solutions to the equation 2x^2=-12x-18 ?

The solutions to the equation 2x^2=-12x-18 are x=-3

Find the zeros of 2x^2=-12x-18

The zeros of 2x^2=-12x-18 are x=-3

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2 x^{2} = - 12 x - 18

x = - 3

Solution steps

2 x^{2} = - 12 x - 18

Move

18

to the left side

2 x^{2} + 18 = - 12 x

Move

12 x

to the left side

2 x^{2} + 18 + 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} + 12 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 2 \cdot 18}{2 \cdot 2}

1 2^{2} - 4 \cdot 2 \cdot 18 = 0

x_{1, 2} = \frac{- 12 \pm 0}{2 \cdot 2}

x = \frac{- 12}{2 \cdot 2}

\frac{- 12}{2 \cdot 2} = - 3

x = - 3

The solution to the quadratic equation is:

x = - 3

- 4 x^{2} + 88 x = 0

2 x^{2} - 2 = 16

x, f = x^{2}

- 3 x^{2} + 9 x - 8 = 0

0 = x^{2} + 2 x - 48

What are the solutions to the equation 2x^2=-12x-18 ?
The solutions to the equation 2x^2=-12x-18 are x=-3
Find the zeros of 2x^2=-12x-18
The zeros of 2x^2=-12x-18 are x=-3