What are the solutions to the equation (m+1)(m+2)=0 ?

The solutions to the equation (m+1)(m+2)=0 are m=-1,m=-2

Find the zeros of (m+1)(m+2)=0

The zeros of (m+1)(m+2)=0 are m=-1,m=-2

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(m + 1) (m + 2) = 0

m = - 1, m = - 2

Solution steps

(m + 1) (m + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

m + 1 = 0 or m + 2 = 0

Solve

m + 1 = 0 : m = - 1

Solve

m + 2 = 0 : m = - 2

The solutions to the quadratic equation are:

m = - 1, m = - 2

x, x^{2} + y^{2} + 6 x - 10 y + 34 = 0

5 x^{2} = 11

9 x^{2} + 9 = 450

x^{2} + 2 = 6 x + 4

7 x^{2} + 5 = 7

What are the solutions to the equation (m+1)(m+2)=0 ?
The solutions to the equation (m+1)(m+2)=0 are m=-1,m=-2
Find the zeros of (m+1)(m+2)=0
The zeros of (m+1)(m+2)=0 are m=-1,m=-2