What are the solutions to the equation 7x^2+5=7 ?

The solutions to the equation 7x^2+5=7 are x=sqrt(2/7),x=-sqrt(2/7)

Find the zeros of 7x^2+5=7

The zeros of 7x^2+5=7 are x=sqrt(2/7),x=-sqrt(2/7)

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7 x^{2} + 5 = 7

x = \frac{2}{7}, x = - \frac{2}{7}

Decimal Notation

x = 0.53452 \dots, x = - 0.53452 \dots

Solution steps

7 x^{2} + 5 = 7

Move

5

to the right side

7 x^{2} = 2

Divide both sides by

7

x^{2} = \frac{2}{7}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{2}{7}, x = - \frac{2}{7}

- 2 x^{2} + x - 44 = 0

2 x^{2} + 12 x + 4 = 0

0 = 3 x^{2} + 4

(3 x - \frac{2}{3})^{2} - 2 = \frac{5}{2}

z^{2} - 144 = 0

What are the solutions to the equation 7x^2+5=7 ?
The solutions to the equation 7x^2+5=7 are x=sqrt(2/7),x=-sqrt(2/7)
Find the zeros of 7x^2+5=7
The zeros of 7x^2+5=7 are x=sqrt(2/7),x=-sqrt(2/7)