What are the solutions to the equation completesquare-x^2-3x+7 ?

The solutions to the equation completesquare-x^2-3x+7 are -(x+3/2)^2+37/4

Find the zeros of completesquare-x^2-3x+7

The zeros of completesquare-x^2-3x+7 are -(x+3/2)^2+37/4

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complete the square

- x^{2} - 3 x + 7

- (x + \frac{3}{2})^{2} + \frac{37}{4}

Solution steps

- x^{2} - 3 x + 7

Write

- x^{2} - 3 x + 7

in the form:

x^{2} + 2 a x + a^{2}

Factor out

- 1

- (x^{2} + 3 x - 7)

2 a = 3 : a = \frac{3}{2}

Add and subtract

(\frac{3}{2})^{2}

- (x^{2} + 3 x - 7 + (\frac{3}{2})^{2} - (\frac{3}{2})^{2})

x^{2} + 2 a x + a^{2} = (x + a)^{2}

x^{2} + 3 x + (\frac{3}{2})^{2} = (x + \frac{3}{2})^{2}

- ((x + \frac{3}{2})^{2} - 7 - (\frac{3}{2})^{2})

Simplify

- (x + \frac{3}{2})^{2} + \frac{37}{4}

(x + 4) (x + 3) = 9^{2}

x^{2} - 7 x + 14 = 7

18 x^{2} - 2 = 0

v, h = \frac{v ^{2}}{2 g}

x, y^{3} - x^{2} + 3 y^{2} + 2 x + 3 y = 0

What are the solutions to the equation completesquare-x^2-3x+7 ?
The solutions to the equation completesquare-x^2-3x+7 are -(x+3/2)^2+37/4
Find the zeros of completesquare-x^2-3x+7
The zeros of completesquare-x^2-3x+7 are -(x+3/2)^2+37/4