What are the solutions to the equation 7x^2-9x-3=-5 ?

The solutions to the equation 7x^2-9x-3=-5 are x=1,x= 2/7

Find the zeros of 7x^2-9x-3=-5

The zeros of 7x^2-9x-3=-5 are x=1,x= 2/7

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7 x^{2} - 9 x - 3 = - 5

x = 1, x = \frac{2}{7}

Decimal Notation

x = 1, x = 0.28571 \dots

Solution steps

7 x^{2} - 9 x - 3 = - 5

Move

5

to the left side

7 x^{2} - 9 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 7 \cdot 2}{2 \cdot 7}

(- 9)^{2} - 4 \cdot 7 \cdot 2 = 5

x_{1, 2} = \frac{- ( - 9 ) \pm 5}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 5}{2 \cdot 7}, x_{2} = \frac{- ( - 9 ) - 5}{2 \cdot 7}

x = \frac{- ( - 9 ) + 5}{2 \cdot 7} : 1

x = \frac{- ( - 9 ) - 5}{2 \cdot 7} : \frac{2}{7}

The solutions to the quadratic equation are:

x = 1, x = \frac{2}{7}

x^{2} - (2 + 5) + 10 = 0

m^{2} + 6 m + 10 = 0

t^{2} - 2 t = 5

x + x^{2} = 90

0 = 2 x^{2} - x + 1

What are the solutions to the equation 7x^2-9x-3=-5 ?
The solutions to the equation 7x^2-9x-3=-5 are x=1,x= 2/7
Find the zeros of 7x^2-9x-3=-5
The zeros of 7x^2-9x-3=-5 are x=1,x= 2/7