What are the solutions to the equation 16x^2+9x-12=4x+9x^2 ?

The solutions to the equation 16x^2+9x-12=4x+9x^2 are x=1,x=-12/7

Find the zeros of 16x^2+9x-12=4x+9x^2

The zeros of 16x^2+9x-12=4x+9x^2 are x=1,x=-12/7

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16 x^{2} + 9 x - 12 = 4 x + 9 x^{2}

x = 1, x = - \frac{12}{7}

Decimal Notation

x = 1, x = - 1.71428 \dots

Solution steps

16 x^{2} + 9 x - 12 = 4 x + 9 x^{2}

Move

9 x^{2}

to the left side

7 x^{2} + 9 x - 12 = 4 x

Move

4 x

to the left side

7 x^{2} + 5 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 7 ( - 12 )}{2 \cdot 7}

5^{2} - 4 \cdot 7 (- 12) = 19

x_{1, 2} = \frac{- 5 \pm 19}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 5 + 19}{2 \cdot 7}, x_{2} = \frac{- 5 - 19}{2 \cdot 7}

x = \frac{- 5 + 19}{2 \cdot 7} : 1

x = \frac{- 5 - 19}{2 \cdot 7} : - \frac{12}{7}

The solutions to the quadratic equation are:

x = 1, x = - \frac{12}{7}

2 x^{2} + 2 x = 24

x, x^{2} y^{2} - 18 x = 3

- 16 t^{2} + 160 t + 120 = 0

5 + 18 x = 35 x^{2}

x, x + y - x^{2} + 2 x y - y^{2} = 0

What are the solutions to the equation 16x^2+9x-12=4x+9x^2 ?
The solutions to the equation 16x^2+9x-12=4x+9x^2 are x=1,x=-12/7
Find the zeros of 16x^2+9x-12=4x+9x^2
The zeros of 16x^2+9x-12=4x+9x^2 are x=1,x=-12/7