What are the solutions to the equation x^2+6x+27=0 ?

The solutions to the equation x^2+6x+27=0 are x=-3+3sqrt(2)i,x=-3-3sqrt(2)i

Find the zeros of x^2+6x+27=0

The zeros of x^2+6x+27=0 are x=-3+3sqrt(2)i,x=-3-3sqrt(2)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 6 x + 27 = 0

x = - 3 + 32 i, x = - 3 - 32 i

Solution steps

x^{2} + 6 x + 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 27}{2 \cdot 1}

Simplify

6^{2} - 4 \cdot 1 \cdot 27 : 62 i

x_{1, 2} = \frac{- 6 \pm 6 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 6 2 i}{2 \cdot 1}, x_{2} = \frac{- 6 - 6 2 i}{2 \cdot 1}

x = \frac{- 6 + 6 2 i}{2 \cdot 1} : - 3 + 32 i

x = \frac{- 6 - 6 2 i}{2 \cdot 1} : - 3 - 32 i

The solutions to the quadratic equation are:

x = - 3 + 32 i, x = - 3 - 32 i

- 3 \cdot \frac{2}{3}

36 w^{2} = 121

1 \cdot 2

5 > ∣ x - 1 ∣

14 x^{2} y^{2} - 28 x^{5} + 56 x^{4}

What are the solutions to the equation x^2+6x+27=0 ?
The solutions to the equation x^2+6x+27=0 are x=-3+3sqrt(2)i,x=-3-3sqrt(2)i
Find the zeros of x^2+6x+27=0
The zeros of x^2+6x+27=0 are x=-3+3sqrt(2)i,x=-3-3sqrt(2)i