What are the solutions to the equation completesquare x^2+5x-21=0 ?

The solutions to the equation completesquare x^2+5x-21=0 are x=(sqrt(109)-5)/2 ,x=(-sqrt(109)-5)/2

Find the zeros of completesquare x^2+5x-21=0

The zeros of completesquare x^2+5x-21=0 are x=(sqrt(109)-5)/2 ,x=(-sqrt(109)-5)/2

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x^{2} + 5 x - 21 = 0

x = \frac{109 - 5}{2}, x = \frac{- 109 - 5}{2}

Decimal Notation

x = 2.72015 \dots, x = - 7.72015 \dots

Solution steps

x^{2} + 5 x - 21 = 0

Move

21

to the right side

x^{2} + 5 x = 21

Rewrite in the form

(x + a)^{2} = b

(x + \frac{5}{2})^{2} = \frac{109}{4}

For

the solutions are

f (x) = a, - a

Solve

x + \frac{5}{2} = \frac{109}{4} : x = \frac{109 - 5}{2}

Solve

x + \frac{5}{2} = - \frac{109}{4} : x = \frac{- 109 - 5}{2}

The solutions to the quadratic equation are:

x = \frac{109 - 5}{2}, x = \frac{- 109 - 5}{2}

x, 2088.4 x^{2} - 15070 x + 5697.2 = 0

(x - 3)^{2} = - 8 (x + 1)

2 x^{2} - 6 x - 5 = 0

2 x^{2} + 9 x - 7 = 0

3 x^{2} + 2 x + 3 = 4

What are the solutions to the equation completesquare x^2+5x-21=0 ?
The solutions to the equation completesquare x^2+5x-21=0 are x=(sqrt(109)-5)/2 ,x=(-sqrt(109)-5)/2
Find the zeros of completesquare x^2+5x-21=0
The zeros of completesquare x^2+5x-21=0 are x=(sqrt(109)-5)/2 ,x=(-sqrt(109)-5)/2