What are the solutions to the equation 0.2x^2-0.9x+1=0 ?

The solutions to the equation 0.2x^2-0.9x+1=0 are x= 5/2 ,x=2

Find the zeros of 0.2x^2-0.9x+1=0

The zeros of 0.2x^2-0.9x+1=0 are x= 5/2 ,x=2

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0.2 x^{2} - 0.9 x + 1 = 0

x = \frac{5}{2}, x = 2

Decimal Notation

x = 2.5, x = 2

Solution steps

0.2 x^{2} - 0.9 x + 1 = 0

Multiply both sides by

10

2 x^{2} - 9 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 2 \cdot 10}{2 \cdot 2}

(- 9)^{2} - 4 \cdot 2 \cdot 10 = 1

x_{1, 2} = \frac{- ( - 9 ) \pm 1}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 1}{2 \cdot 2}, x_{2} = \frac{- ( - 9 ) - 1}{2 \cdot 2}

x = \frac{- ( - 9 ) + 1}{2 \cdot 2} : \frac{5}{2}

x = \frac{- ( - 9 ) - 1}{2 \cdot 2} : 2

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = 2

x^{2} + x + 42 = 0

(7 x + 5)^{2} = 48

6 x^{2} - 208 x + 1280 = 0

15 x^{2} + 7 x - 2 = 0

\frac{x}{9} \cdot \frac{x}{9} = \frac{4}{9}

What are the solutions to the equation 0.2x^2-0.9x+1=0 ?
The solutions to the equation 0.2x^2-0.9x+1=0 are x= 5/2 ,x=2
Find the zeros of 0.2x^2-0.9x+1=0
The zeros of 0.2x^2-0.9x+1=0 are x= 5/2 ,x=2