What are the solutions to the equation 9x^2+18x+79=0 ?

The solutions to the equation 9x^2+18x+79=0 are x=-1+i(sqrt(70))/3 ,x=-1-i(sqrt(70))/3

Find the zeros of 9x^2+18x+79=0

The zeros of 9x^2+18x+79=0 are x=-1+i(sqrt(70))/3 ,x=-1-i(sqrt(70))/3

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9 x^{2} + 18 x + 79 = 0

x = - 1 + i \frac{70}{3}, x = - 1 - i \frac{70}{3}

Solution steps

9 x^{2} + 18 x + 79 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 9 \cdot 79}{2 \cdot 9}

Simplify

1 8^{2} - 4 \cdot 9 \cdot 79 : 670 i

x_{1, 2} = \frac{- 18 \pm 6 70 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 18 + 6 70 i}{2 \cdot 9}, x_{2} = \frac{- 18 - 6 70 i}{2 \cdot 9}

x = \frac{- 18 + 6 70 i}{2 \cdot 9} : - 1 + i \frac{70}{3}

x = \frac{- 18 - 6 70 i}{2 \cdot 9} : - 1 - i \frac{70}{3}

The solutions to the quadratic equation are:

x = - 1 + i \frac{70}{3}, x = - 1 - i \frac{70}{3}

3 m^{2} + 16 m + 21 = 0

x^{2} + 11 + 30 = 0

5 x^{2} + 1 = - 9

3 y^{2} - 7 y = 0

8 x^{2} + 50 = 0

What are the solutions to the equation 9x^2+18x+79=0 ?
The solutions to the equation 9x^2+18x+79=0 are x=-1+i(sqrt(70))/3 ,x=-1-i(sqrt(70))/3
Find the zeros of 9x^2+18x+79=0
The zeros of 9x^2+18x+79=0 are x=-1+i(sqrt(70))/3 ,x=-1-i(sqrt(70))/3