What are the solutions to the equation 24x^2-48x=0 ?

The solutions to the equation 24x^2-48x=0 are x=2,x=0

Find the zeros of 24x^2-48x=0

The zeros of 24x^2-48x=0 are x=2,x=0

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24 x^{2} - 48 x = 0

x = 2, x = 0

Solution steps

24 x^{2} - 48 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 48 ) \pm ( - 48 ) ^{2} - 4 \cdot 24 \cdot 0}{2 \cdot 24}

(- 48)^{2} - 4 \cdot 24 \cdot 0 = 48

x_{1, 2} = \frac{- ( - 48 ) \pm 48}{2 \cdot 24}

Separate the solutions

x_{1} = \frac{- ( - 48 ) + 48}{2 \cdot 24}, x_{2} = \frac{- ( - 48 ) - 48}{2 \cdot 24}

x = \frac{- ( - 48 ) + 48}{2 \cdot 24} : 2

x = \frac{- ( - 48 ) - 48}{2 \cdot 24} : 0

The solutions to the quadratic equation are:

x = 2, x = 0

s^{2} - s - 1

x^{2} = 5 + x

12 x^{2} = 9 x

x^{2} = 480

x^{2} + \frac{63 x}{5} + \frac{101}{4} = 0

What are the solutions to the equation 24x^2-48x=0 ?
The solutions to the equation 24x^2-48x=0 are x=2,x=0
Find the zeros of 24x^2-48x=0
The zeros of 24x^2-48x=0 are x=2,x=0