What are the solutions to the equation -3x^2+21x-36=0 ?

The solutions to the equation -3x^2+21x-36=0 are x=3,x=4

Find the zeros of -3x^2+21x-36=0

The zeros of -3x^2+21x-36=0 are x=3,x=4

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- 3 x^{2} + 21 x - 36 = 0

x = 3, x = 4

Solution steps

- 3 x^{2} + 21 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 21 \pm 2 1 ^{2} - 4 ( - 3 ) ( - 36 )}{2 ( - 3 )}

2 1^{2} - 4 (- 3) (- 36) = 3

x_{1, 2} = \frac{- 21 \pm 3}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 21 + 3}{2 ( - 3 )}, x_{2} = \frac{- 21 - 3}{2 ( - 3 )}

x = \frac{- 21 + 3}{2 ( - 3 )} : 3

x = \frac{- 21 - 3}{2 ( - 3 )} : 4

The solutions to the quadratic equation are:

x = 3, x = 4

α, x^{2} + α^{2} y^{2} = 4 α^{2}

5 w^{2} = 30 w

(3 x - 1)^{2} = 3 x + 1

9 x^{2} - 35 = 14

5 = \frac{x}{9} 9 x

What are the solutions to the equation -3x^2+21x-36=0 ?
The solutions to the equation -3x^2+21x-36=0 are x=3,x=4
Find the zeros of -3x^2+21x-36=0
The zeros of -3x^2+21x-36=0 are x=3,x=4