What are the solutions to the equation x^2-18x-16=-1 ?

The solutions to the equation x^2-18x-16=-1 are x=9+4sqrt(6),x=9-4sqrt(6)

Find the zeros of x^2-18x-16=-1

The zeros of x^2-18x-16=-1 are x=9+4sqrt(6),x=9-4sqrt(6)

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x^{2} - 18 x - 16 = - 1

x = 9 + 46, x = 9 - 46

Decimal Notation

x = 18.79795 \dots, x = - 0.79795 \dots

Solution steps

x^{2} - 18 x - 16 = - 1

Move

1

to the left side

x^{2} - 18 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot ( - 15 )}{2 \cdot 1}

(- 18)^{2} - 4 \cdot 1 \cdot (- 15) = 86

x_{1, 2} = \frac{- ( - 18 ) \pm 8 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 8 6}{2 \cdot 1}, x_{2} = \frac{- ( - 18 ) - 8 6}{2 \cdot 1}

x = \frac{- ( - 18 ) + 8 6}{2 \cdot 1} : 9 + 46

x = \frac{- ( - 18 ) - 8 6}{2 \cdot 1} : 9 - 46

The solutions to the quadratic equation are:

x = 9 + 46, x = 9 - 46

8 x^{2} - 3 x + 1 = 0

r, v = n r^{2} h

m^{2} + 36 = 0

x^{2} = 1.5

x^{2} - 5 x - 6 = 0

What are the solutions to the equation x^2-18x-16=-1 ?
The solutions to the equation x^2-18x-16=-1 are x=9+4sqrt(6),x=9-4sqrt(6)
Find the zeros of x^2-18x-16=-1
The zeros of x^2-18x-16=-1 are x=9+4sqrt(6),x=9-4sqrt(6)