What are the solutions to the equation z^2+14z+45=0 ?

The solutions to the equation z^2+14z+45=0 are z=-5,z=-9

Find the zeros of z^2+14z+45=0

The zeros of z^2+14z+45=0 are z=-5,z=-9

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z^{2} + 14 z + 45 = 0

z = - 5, z = - 9

Solution steps

z^{2} + 14 z + 45 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 45}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot 45 = 4

z_{1, 2} = \frac{- 14 \pm 4}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- 14 + 4}{2 \cdot 1}, z_{2} = \frac{- 14 - 4}{2 \cdot 1}

z = \frac{- 14 + 4}{2 \cdot 1} : - 5

z = \frac{- 14 - 4}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

z = - 5, z = - 9

x^{2} - 2 x

x, x^{2} + 7 x - 18 = 0

2 x^{2} - x - 55 = 0

2 x^{2} - 5 x - 13 = 0

2 x^{2} - 2 x = 7

What are the solutions to the equation z^2+14z+45=0 ?
The solutions to the equation z^2+14z+45=0 are z=-5,z=-9
Find the zeros of z^2+14z+45=0
The zeros of z^2+14z+45=0 are z=-5,z=-9