What are the solutions to the equation m^2+m+3=0 ?

The solutions to the equation m^2+m+3=0 are m=-1/2+i(sqrt(11))/2 ,m=-1/2-i(sqrt(11))/2

Find the zeros of m^2+m+3=0

The zeros of m^2+m+3=0 are m=-1/2+i(sqrt(11))/2 ,m=-1/2-i(sqrt(11))/2

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m^{2} + m + 3 = 0

m = - \frac{1}{2} + i \frac{11}{2}, m = - \frac{1}{2} - i \frac{11}{2}

Solution steps

m^{2} + m + 3 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

Simplify

1^{2} - 4 \cdot 1 \cdot 3 : 11 i

m_{1, 2} = \frac{- 1 \pm 11 i}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 1 + 11 i}{2 \cdot 1}, m_{2} = \frac{- 1 - 11 i}{2 \cdot 1}

m = \frac{- 1 + 11 i}{2 \cdot 1} : - \frac{1}{2} + i \frac{11}{2}

m = \frac{- 1 - 11 i}{2 \cdot 1} : - \frac{1}{2} - i \frac{11}{2}

The solutions to the quadratic equation are:

m = - \frac{1}{2} + i \frac{11}{2}, m = - \frac{1}{2} - i \frac{11}{2}

4 < 5 - 3 x < 7

6 a^{2} - 13 ab - 5 b^{2}

\frac{1}{3} (9)^{\frac{3}{2}}

(4 - 2 x) + (5 x - 3) = (x - 2) - (x + 3)

62 \cdot 62

What are the solutions to the equation m^2+m+3=0 ?
The solutions to the equation m^2+m+3=0 are m=-1/2+i(sqrt(11))/2 ,m=-1/2-i(sqrt(11))/2
Find the zeros of m^2+m+3=0
The zeros of m^2+m+3=0 are m=-1/2+i(sqrt(11))/2 ,m=-1/2-i(sqrt(11))/2