What are the solutions to the equation 0=x^2-14x+46 ?

The solutions to the equation 0=x^2-14x+46 are x=7+sqrt(3),x=7-sqrt(3)

Find the zeros of 0=x^2-14x+46

The zeros of 0=x^2-14x+46 are x=7+sqrt(3),x=7-sqrt(3)

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0 = x^{2} - 14 x + 46

x = 7 + 3, x = 7 - 3

Decimal Notation

x = 8.73205 \dots, x = 5.26794 \dots

Solution steps

0 = x^{2} - 14 x + 46

Switch sides

x^{2} - 14 x + 46 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 46}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 46 = 23

x_{1, 2} = \frac{- ( - 14 ) \pm 2 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 2 3}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 2 3}{2 \cdot 1}

x = \frac{- ( - 14 ) + 2 3}{2 \cdot 1} : 7 + 3

x = \frac{- ( - 14 ) - 2 3}{2 \cdot 1} : 7 - 3

The solutions to the quadratic equation are:

x = 7 + 3, x = 7 - 3

x, x^{2} + z^{2} = 0

9 = - 4 x^{2} - x

- a^{2} - 2 a + 3 = 0

a^{2} + 10 a - 12 = 0

a = a^{2} + (2 - \frac{4}{3} a)^{2} (\frac{3}{4})

What are the solutions to the equation 0=x^2-14x+46 ?
The solutions to the equation 0=x^2-14x+46 are x=7+sqrt(3),x=7-sqrt(3)
Find the zeros of 0=x^2-14x+46
The zeros of 0=x^2-14x+46 are x=7+sqrt(3),x=7-sqrt(3)