What are the solutions to the equation 3(7x-9)-(7x-9)^2=0 ?

The solutions to the equation 3(7x-9)-(7x-9)^2=0 are x= 9/7 ,x= 12/7

Find the zeros of 3(7x-9)-(7x-9)^2=0

The zeros of 3(7x-9)-(7x-9)^2=0 are x= 9/7 ,x= 12/7

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3 (7 x - 9) - (7 x - 9)^{2} = 0

x = \frac{9}{7}, x = \frac{12}{7}

Decimal Notation

x = 1.28571 \dots, x = 1.71428 \dots

Solution steps

3 (7 x - 9) - (7 x - 9)^{2} = 0

Expand

3 (7 x - 9) - (7 x - 9)^{2} : - 49 x^{2} + 147 x - 108

- 49 x^{2} + 147 x - 108 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 147 \pm 14 7 ^{2} - 4 ( - 49 ) ( - 108 )}{2 ( - 49 )}

14 7^{2} - 4 (- 49) (- 108) = 21

x_{1, 2} = \frac{- 147 \pm 21}{2 ( - 49 )}

Separate the solutions

x_{1} = \frac{- 147 + 21}{2 ( - 49 )}, x_{2} = \frac{- 147 - 21}{2 ( - 49 )}

x = \frac{- 147 + 21}{2 ( - 49 )} : \frac{9}{7}

x = \frac{- 147 - 21}{2 ( - 49 )} : \frac{12}{7}

The solutions to the quadratic equation are:

x = \frac{9}{7}, x = \frac{12}{7}

x (x - 1) + 2 x - 2 = 0

(x + 2)^{2} - 6 = 30

5 x^{2} + 10 x - 4 = 0

2 x^{2} + 20 x + 82 = 0

x^{2} + 4 x^{2} = 4

What are the solutions to the equation 3(7x-9)-(7x-9)^2=0 ?
The solutions to the equation 3(7x-9)-(7x-9)^2=0 are x= 9/7 ,x= 12/7
Find the zeros of 3(7x-9)-(7x-9)^2=0
The zeros of 3(7x-9)-(7x-9)^2=0 are x= 9/7 ,x= 12/7