What are the solutions to the equation -6x^2+4x-3=0 ?

The solutions to the equation -6x^2+4x-3=0 are x= 1/3-i(sqrt(14))/6 ,x= 1/3+i(sqrt(14))/6

Find the zeros of -6x^2+4x-3=0

The zeros of -6x^2+4x-3=0 are x= 1/3-i(sqrt(14))/6 ,x= 1/3+i(sqrt(14))/6

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- 6 x^{2} + 4 x - 3 = 0

x = \frac{1}{3} - i \frac{14}{6}, x = \frac{1}{3} + i \frac{14}{6}

Solution steps

- 6 x^{2} + 4 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 6 ) ( - 3 )}{2 ( - 6 )}

Simplify

4^{2} - 4 (- 6) (- 3) : 214 i

x_{1, 2} = \frac{- 4 \pm 2 14 i}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- 4 + 2 14 i}{2 ( - 6 )}, x_{2} = \frac{- 4 - 2 14 i}{2 ( - 6 )}

x = \frac{- 4 + 2 14 i}{2 ( - 6 )} : \frac{1}{3} - i \frac{14}{6}

x = \frac{- 4 - 2 14 i}{2 ( - 6 )} : \frac{1}{3} + i \frac{14}{6}

The solutions to the quadratic equation are:

x = \frac{1}{3} - i \frac{14}{6}, x = \frac{1}{3} + i \frac{14}{6}

18 n = 2 n^{2}

- 6 x^{2} - 5 x + 6 = 0

0 = - x^{2} - 8 x - 16

3 x^{2} + 6 x + 2

x^{2} + 8 x + 12 = 0

What are the solutions to the equation -6x^2+4x-3=0 ?
The solutions to the equation -6x^2+4x-3=0 are x= 1/3-i(sqrt(14))/6 ,x= 1/3+i(sqrt(14))/6
Find the zeros of -6x^2+4x-3=0
The zeros of -6x^2+4x-3=0 are x= 1/3-i(sqrt(14))/6 ,x= 1/3+i(sqrt(14))/6