What are the solutions to the equation completesquare x^2+8x+12=0 ?

The solutions to the equation completesquare x^2+8x+12=0 are x=-2,x=-6

Find the zeros of completesquare x^2+8x+12=0

The zeros of completesquare x^2+8x+12=0 are x=-2,x=-6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 8 x + 12 = 0

x = - 2, x = - 6

Solution steps

x^{2} + 8 x + 12 = 0

Move

12

to the right side

x^{2} + 8 x = - 12

Rewrite in the form

(x + a)^{2} = b

(x + 4)^{2} = 4

For

the solutions are

f (x) = a, - a

Solve

x + 4 = 4 : x = - 2

Solve

x + 4 = - 4 : x = - 6

The solutions to the quadratic equation are:

x = - 2, x = - 6

12 x^{2} + 17 x - 40 = 0

3 x^{2} + 6 x - 2

x^{2} - 11 x + 21 = 0

x^{2} - \frac{3}{2} x + 1 = 0

x, x^{2} + y^{3} - 2 y = 3

What are the solutions to the equation completesquare x^2+8x+12=0 ?
The solutions to the equation completesquare x^2+8x+12=0 are x=-2,x=-6
Find the zeros of completesquare x^2+8x+12=0
The zeros of completesquare x^2+8x+12=0 are x=-2,x=-6