What are the solutions to the equation -2x^2+8x-6=0 ?

The solutions to the equation -2x^2+8x-6=0 are x=1,x=3

Find the zeros of -2x^2+8x-6=0

The zeros of -2x^2+8x-6=0 are x=1,x=3

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- 2 x^{2} + 8 x - 6 = 0

x = 1, x = 3

Solution steps

- 2 x^{2} + 8 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 2 ) ( - 6 )}{2 ( - 2 )}

8^{2} - 4 (- 2) (- 6) = 4

x_{1, 2} = \frac{- 8 \pm 4}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 8 + 4}{2 ( - 2 )}, x_{2} = \frac{- 8 - 4}{2 ( - 2 )}

x = \frac{- 8 + 4}{2 ( - 2 )} : 1

x = \frac{- 8 - 4}{2 ( - 2 )} : 3

The solutions to the quadratic equation are:

x = 1, x = 3

x^{4} - 9 x^{3} + 9 x^{2} + 33 x + 14

∣ 5 - 7 x ∣ < - 1

251.99 \cdot 6.022 \cdot 1 0^{23}

296 > d - 505

8 a^{3} + 27 b^{6}

What are the solutions to the equation -2x^2+8x-6=0 ?
The solutions to the equation -2x^2+8x-6=0 are x=1,x=3
Find the zeros of -2x^2+8x-6=0
The zeros of -2x^2+8x-6=0 are x=1,x=3