What are the solutions to the equation x^2-16x+35=0 ?

The solutions to the equation x^2-16x+35=0 are x=8+sqrt(29),x=8-sqrt(29)

Find the zeros of x^2-16x+35=0

The zeros of x^2-16x+35=0 are x=8+sqrt(29),x=8-sqrt(29)

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x^{2} - 16 x + 35 = 0

x = 8 + 29, x = 8 - 29

Decimal Notation

x = 13.38516 \dots, x = 2.61483 \dots

Solution steps

x^{2} - 16 x + 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 35}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot 35 = 229

x_{1, 2} = \frac{- ( - 16 ) \pm 2 29}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 2 29}{2 \cdot 1}, x_{2} = \frac{- ( - 16 ) - 2 29}{2 \cdot 1}

x = \frac{- ( - 16 ) + 2 29}{2 \cdot 1} : 8 + 29

x = \frac{- ( - 16 ) - 2 29}{2 \cdot 1} : 8 - 29

The solutions to the quadratic equation are:

x = 8 + 29, x = 8 - 29

x^{2} + (x + 2)^{2} = 10

\frac{5}{6} x - \frac{2}{9} x^{2} = 0

y^{2} - 72 = 0

3 x (x - 7) = 0

- 4 x^{2} - 42 x + 22 = 0

What are the solutions to the equation x^2-16x+35=0 ?
The solutions to the equation x^2-16x+35=0 are x=8+sqrt(29),x=8-sqrt(29)
Find the zeros of x^2-16x+35=0
The zeros of x^2-16x+35=0 are x=8+sqrt(29),x=8-sqrt(29)