What are the solutions to the equation v^2+3v-28=0 ?

The solutions to the equation v^2+3v-28=0 are v=4,v=-7

Find the zeros of v^2+3v-28=0

The zeros of v^2+3v-28=0 are v=4,v=-7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

v^{2} + 3 v - 28 = 0

v = 4, v = - 7

Solution steps

v^{2} + 3 v - 28 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 28 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 28) = 11

v_{1, 2} = \frac{- 3 \pm 11}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- 3 + 11}{2 \cdot 1}, v_{2} = \frac{- 3 - 11}{2 \cdot 1}

v = \frac{- 3 + 11}{2 \cdot 1} : 4

v = \frac{- 3 - 11}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

v = 4, v = - 7

x^{2} - 13 x + 36 = 0

30 v = 9 v^{2} + 25

x^{2} - 2 (m^{2} - 4 m) x + m^{4} = 0

x, x^{2} + 5 x y = 9 x + 3 y

(2 x - 1) (x - 4) = 0

What are the solutions to the equation v^2+3v-28=0 ?
The solutions to the equation v^2+3v-28=0 are v=4,v=-7
Find the zeros of v^2+3v-28=0
The zeros of v^2+3v-28=0 are v=4,v=-7