What are the solutions to the equation x^2-5ax+3a=0 ?

The solutions to the equation x^2-5ax+3a=0 are x=(5a+sqrt(25a^2-12a))/2 ,x=(5a-sqrt(25a^2-12a))/2

Find the zeros of x^2-5ax+3a=0

The zeros of x^2-5ax+3a=0 are x=(5a+sqrt(25a^2-12a))/2 ,x=(5a-sqrt(25a^2-12a))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 5 a x + 3 a = 0

x = \frac{5 a + 25 a ^{2} - 12 a}{2}, x = \frac{5 a - 25 a ^{2} - 12 a}{2}

Solution steps

x^{2} - 5 a x + 3 a = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 a ) \pm ( - 5 a ) ^{2} - 4 \cdot 1 \cdot 3 a}{2 \cdot 1}

Simplify

(- 5 a)^{2} - 4 \cdot 1 \cdot 3 a : 25 a^{2} - 12 a

x_{1, 2} = \frac{- ( - 5 a ) \pm 25 a ^{2} - 12 a}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 a ) + 25 a ^{2} - 12 a}{2 \cdot 1}, x_{2} = \frac{- ( - 5 a ) - 25 a ^{2} - 12 a}{2 \cdot 1}

x = \frac{- ( - 5 a ) + 25 a ^{2} - 12 a}{2 \cdot 1} : \frac{5 a + 25 a ^{2} - 12 a}{2}

x = \frac{- ( - 5 a ) - 25 a ^{2} - 12 a}{2 \cdot 1} : \frac{5 a - 25 a ^{2} - 12 a}{2}

The solutions to the quadratic equation are:

x = \frac{5 a + 25 a ^{2} - 12 a}{2}, x = \frac{5 a - 25 a ^{2} - 12 a}{2}

x^{2} - 2 x - 32 = 30

x^{2} - 45 = 44

16 - x^{2} = 9 x^{2} + 16

2 x^{2} + x = 2

2 x^{2} + x = 9

What are the solutions to the equation x^2-5ax+3a=0 ?
The solutions to the equation x^2-5ax+3a=0 are x=(5a+sqrt(25a^2-12a))/2 ,x=(5a-sqrt(25a^2-12a))/2
Find the zeros of x^2-5ax+3a=0
The zeros of x^2-5ax+3a=0 are x=(5a+sqrt(25a^2-12a))/2 ,x=(5a-sqrt(25a^2-12a))/2