What are the solutions to the equation v^2-15=-2v ?

The solutions to the equation v^2-15=-2v are v=3,v=-5

Find the zeros of v^2-15=-2v

The zeros of v^2-15=-2v are v=3,v=-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

v^{2} - 15 = - 2 v

v = 3, v = - 5

Solution steps

v^{2} - 15 = - 2 v

Move

2 v

to the left side

v^{2} - 15 + 2 v = 0

Write in the standard form

a x^{2} + b x + c = 0

v^{2} + 2 v - 15 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 15 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 15) = 8

v_{1, 2} = \frac{- 2 \pm 8}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- 2 + 8}{2 \cdot 1}, v_{2} = \frac{- 2 - 8}{2 \cdot 1}

v = \frac{- 2 + 8}{2 \cdot 1} : 3

v = \frac{- 2 - 8}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

v = 3, v = - 5

\frac{( y - 1 ) ^{2}}{49} - \frac{( y - 1 ) ^{2}}{36} = 1

x^{2} - 6 x + 8 = - x^{2} + 7 x - 10

- 3 x^{2} - 7 x + 2 = 0

x^{2} = 2 (x + 4)

c^{2} - 100 = 0

What are the solutions to the equation v^2-15=-2v ?
The solutions to the equation v^2-15=-2v are v=3,v=-5
Find the zeros of v^2-15=-2v
The zeros of v^2-15=-2v are v=3,v=-5