What are the solutions to the equation 1^2+x^2=5^2 ?

The solutions to the equation 1^2+x^2=5^2 are x=2sqrt(6),x=-2sqrt(6)

Find the zeros of 1^2+x^2=5^2

The zeros of 1^2+x^2=5^2 are x=2sqrt(6),x=-2sqrt(6)

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1^{2} + x^{2} = 5^{2}

x = 26, x = - 26

Decimal Notation

x = 4.89897 \dots, x = - 4.89897 \dots

Solution steps

1^{2} + x^{2} = 5^{2}

Move

1^{2}

to the right side

x^{2} = 24

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 24, x = - 24

24 = 26

- 24 = - 26

x = 26, x = - 26

3 y^{2} - 9 y = 0

7 x^{2} + 3 x - 5 = 0

(2 x - 7 x)^{2} + 9 (2 x^{2} - 7 x) + 18 = 0

x = - 3 x^{2}

2 x^{2} + 14 x - 18 = 0

What are the solutions to the equation 1^2+x^2=5^2 ?
The solutions to the equation 1^2+x^2=5^2 are x=2sqrt(6),x=-2sqrt(6)
Find the zeros of 1^2+x^2=5^2
The zeros of 1^2+x^2=5^2 are x=2sqrt(6),x=-2sqrt(6)