What are the solutions to the equation (1/4)^2+x^2=1 ?

The solutions to the equation (1/4)^2+x^2=1 are x=(sqrt(15))/4 ,x=-(sqrt(15))/4

Find the zeros of (1/4)^2+x^2=1

The zeros of (1/4)^2+x^2=1 are x=(sqrt(15))/4 ,x=-(sqrt(15))/4

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(\frac{1}{4})^{2} + x^{2} = 1

x = \frac{15}{4}, x = - \frac{15}{4}

Decimal Notation

x = 0.96824 \dots, x = - 0.96824 \dots

Solution steps

(\frac{1}{4})^{2} + x^{2} = 1

Expand

(\frac{1}{4})^{2} + x^{2} : \frac{1}{16} + x^{2}

\frac{1}{16} + x^{2} = 1

Move

\frac{1}{16}

to the right side

x^{2} = 1 - \frac{1}{16}

Simplify

1 - \frac{1}{16} : \frac{15}{16}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{15}{16}, x = - \frac{15}{16}

\frac{15}{16} = \frac{15}{4}

- \frac{15}{16} = - \frac{15}{4}

x = \frac{15}{4}, x = - \frac{15}{4}

2 y^{2} + 6 y - 7 = 0

p, p^{2} = a^{3}

t, v = t^{2} - 38

5.6 - 7 - 5 x - 19.3 x^{2} = 0

x^{2} + x + 2 = 9

What are the solutions to the equation (1/4)^2+x^2=1 ?
The solutions to the equation (1/4)^2+x^2=1 are x=(sqrt(15))/4 ,x=-(sqrt(15))/4
Find the zeros of (1/4)^2+x^2=1
The zeros of (1/4)^2+x^2=1 are x=(sqrt(15))/4 ,x=-(sqrt(15))/4