What are the solutions to the equation 2x^2+3x+9/8 =0 ?

The solutions to the equation 2x^2+3x+9/8 =0 are x=-3/4

Find the zeros of 2x^2+3x+9/8 =0

The zeros of 2x^2+3x+9/8 =0 are x=-3/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} + 3 x + \frac{9}{8} = 0

x = - \frac{3}{4}

Decimal Notation

x = - 0.75

Solution steps

2 x^{2} + 3 x + \frac{9}{8} = 0

Multiply both sides by

8

16 x^{2} + 24 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 16 \cdot 9}{2 \cdot 16}

2 4^{2} - 4 \cdot 16 \cdot 9 = 0

x_{1, 2} = \frac{- 24 \pm 0}{2 \cdot 16}

x = \frac{- 24}{2 \cdot 16}

\frac{- 24}{2 \cdot 16} = - \frac{3}{4}

x = - \frac{3}{4}

The solution to the quadratic equation is:

x = - \frac{3}{4}

2 (x^{2} + 9) = 26

- 10 x + 175 - 5 x^{2} = 0

192 x - 6 x^{2} = 0

x^{2} - 7 x + 7 = 35

4 (x - 6)^{2} - 35 = 14

What are the solutions to the equation 2x^2+3x+9/8 =0 ?
The solutions to the equation 2x^2+3x+9/8 =0 are x=-3/4
Find the zeros of 2x^2+3x+9/8 =0
The zeros of 2x^2+3x+9/8 =0 are x=-3/4