What are the solutions to the equation 3x^2-7x-26=0 ?

The solutions to the equation 3x^2-7x-26=0 are x= 13/3 ,x=-2

Find the zeros of 3x^2-7x-26=0

The zeros of 3x^2-7x-26=0 are x= 13/3 ,x=-2

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3 x^{2} - 7 x - 26 = 0

x = \frac{13}{3}, x = - 2

Decimal Notation

x = 4.33333 \dots, x = - 2

Solution steps

3 x^{2} - 7 x - 26 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 3 ( - 26 )}{2 \cdot 3}

(- 7)^{2} - 4 \cdot 3 (- 26) = 19

x_{1, 2} = \frac{- ( - 7 ) \pm 19}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 19}{2 \cdot 3}, x_{2} = \frac{- ( - 7 ) - 19}{2 \cdot 3}

x = \frac{- ( - 7 ) + 19}{2 \cdot 3} : \frac{13}{3}

x = \frac{- ( - 7 ) - 19}{2 \cdot 3} : - 2

The solutions to the quadratic equation are:

x = \frac{13}{3}, x = - 2

486 + 108 x + 6 x^{2}

2 \cdot 32

\frac{1}{\frac{2}{\frac{3}{2}}}

5 u^{2} - 14 u - 3

- 6 a^{2} + 48 a - 64

What are the solutions to the equation 3x^2-7x-26=0 ?
The solutions to the equation 3x^2-7x-26=0 are x= 13/3 ,x=-2
Find the zeros of 3x^2-7x-26=0
The zeros of 3x^2-7x-26=0 are x= 13/3 ,x=-2