What are the solutions to the equation (x^2)/2+(13x)/(20)= 3/2 ?

The solutions to the equation (x^2)/2+(13x)/(20)= 3/2 are x= 6/5 ,x=-5/2

Find the zeros of (x^2)/2+(13x)/(20)= 3/2

The zeros of (x^2)/2+(13x)/(20)= 3/2 are x= 6/5 ,x=-5/2

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\frac{x ^{2}}{2} + \frac{13 x}{20} = \frac{3}{2}

x = \frac{6}{5}, x = - \frac{5}{2}

Decimal Notation

x = 1.2, x = - 2.5

Solution steps

\frac{x ^{2}}{2} + \frac{13 x}{20} = \frac{3}{2}

Find Least Common Multiplier of

2, 20 : 20

Multiply by LCM=

20

\frac{x ^{2}}{2} \cdot 20 + \frac{13 x}{20} \cdot 20 = \frac{3}{2} \cdot 20

Simplify

10 x^{2} + 13 x = 30

Move

30

to the left side

10 x^{2} + 13 x - 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 10 ( - 30 )}{2 \cdot 10}

1 3^{2} - 4 \cdot 10 (- 30) = 37

x_{1, 2} = \frac{- 13 \pm 37}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 13 + 37}{2 \cdot 10}, x_{2} = \frac{- 13 - 37}{2 \cdot 10}

x = \frac{- 13 + 37}{2 \cdot 10} : \frac{6}{5}

x = \frac{- 13 - 37}{2 \cdot 10} : - \frac{5}{2}

The solutions to the quadratic equation are:

x = \frac{6}{5}, x = - \frac{5}{2}

\frac{1}{2} \cdot 2.1 \cdot v^{2} = 6.5

12 y^{2} + 2 y - 2 = 0

q^{2} + 4 q + 4 = 0

(2 x + 3)^{2} - 4 (x - 1) (x + 3) = x^{2}

x^{2} - 2 x - 80 = 0

What are the solutions to the equation (x^2)/2+(13x)/(20)= 3/2 ?
The solutions to the equation (x^2)/2+(13x)/(20)= 3/2 are x= 6/5 ,x=-5/2
Find the zeros of (x^2)/2+(13x)/(20)= 3/2
The zeros of (x^2)/2+(13x)/(20)= 3/2 are x= 6/5 ,x=-5/2