What are the solutions to the equation completesquare x^2-7x+12=0 ?

The solutions to the equation completesquare x^2-7x+12=0 are x=4,x=3

Find the zeros of completesquare x^2-7x+12=0

The zeros of completesquare x^2-7x+12=0 are x=4,x=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 7 x + 12 = 0

x = 4, x = 3

Solution steps

x^{2} - 7 x + 12 = 0

Move

12

to the right side

x^{2} - 7 x = - 12

Rewrite in the form

(x + a)^{2} = b

(x - \frac{7}{2})^{2} = \frac{1}{4}

For

the solutions are

f (x) = a, - a

Solve

x - \frac{7}{2} = \frac{1}{4} : x = 4

Solve

x - \frac{7}{2} = - \frac{1}{4} : x = 3

The solutions to the quadratic equation are:

x = 4, x = 3

3 x^{2} = x^{2} + 2

290 = \frac{9.81 \cdot t ^{2}}{2}

m x^{2} + (m - 2) x - (3 m - 1) = 0

x^{2} - \frac{2 3}{3} x + \frac{1}{3} = 0

462.28 = 12.146 + 7.473 x - 0.092 x^{2}

What are the solutions to the equation completesquare x^2-7x+12=0 ?
The solutions to the equation completesquare x^2-7x+12=0 are x=4,x=3
Find the zeros of completesquare x^2-7x+12=0
The zeros of completesquare x^2-7x+12=0 are x=4,x=3