What are the solutions to the equation (x+4)(x-2)=3 ?

The solutions to the equation (x+4)(x-2)=3 are x=-1+2sqrt(3),x=-1-2sqrt(3)

Find the zeros of (x+4)(x-2)=3

The zeros of (x+4)(x-2)=3 are x=-1+2sqrt(3),x=-1-2sqrt(3)

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(x + 4) (x - 2) = 3

x = - 1 + 23, x = - 1 - 23

Decimal Notation

x = 2.46410 \dots, x = - 4.46410 \dots

Solution steps

(x + 4) (x - 2) = 3

Expand

(x + 4) (x - 2) : x^{2} + 2 x - 8

x^{2} + 2 x - 8 = 3

Move

3

to the left side

x^{2} + 2 x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 11 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 11) = 43

x_{1, 2} = \frac{- 2 \pm 4 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 4 3}{2 \cdot 1}, x_{2} = \frac{- 2 - 4 3}{2 \cdot 1}

x = \frac{- 2 + 4 3}{2 \cdot 1} : - 1 + 23

x = \frac{- 2 - 4 3}{2 \cdot 1} : - 1 - 23

The solutions to the quadratic equation are:

x = - 1 + 23, x = - 1 - 23

x^{2} + 2 x (- x + 2) - 3 (- x + 2)^{2} = 0

5 x^{2} = 6 x - 1

3 u^{2} + 24 u = 0

16 x^{2} = - 56 x - 18

x^{2} + 5 x + 1 = 0

What are the solutions to the equation (x+4)(x-2)=3 ?
The solutions to the equation (x+4)(x-2)=3 are x=-1+2sqrt(3),x=-1-2sqrt(3)
Find the zeros of (x+4)(x-2)=3
The zeros of (x+4)(x-2)=3 are x=-1+2sqrt(3),x=-1-2sqrt(3)