What are the solutions to the equation 3v^2+2v-8=0 ?

The solutions to the equation 3v^2+2v-8=0 are v= 4/3 ,v=-2

Find the zeros of 3v^2+2v-8=0

The zeros of 3v^2+2v-8=0 are v= 4/3 ,v=-2

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3 v^{2} + 2 v - 8 = 0

v = \frac{4}{3}, v = - 2

Decimal Notation

v = 1.33333 \dots, v = - 2

Solution steps

3 v^{2} + 2 v - 8 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 3 ( - 8 )}{2 \cdot 3}

2^{2} - 4 \cdot 3 (- 8) = 10

v_{1, 2} = \frac{- 2 \pm 10}{2 \cdot 3}

Separate the solutions

v_{1} = \frac{- 2 + 10}{2 \cdot 3}, v_{2} = \frac{- 2 - 10}{2 \cdot 3}

v = \frac{- 2 + 10}{2 \cdot 3} : \frac{4}{3}

v = \frac{- 2 - 10}{2 \cdot 3} : - 2

The solutions to the quadratic equation are:

v = \frac{4}{3}, v = - 2

x^{2} + 11 x = - 18

x^{2} - 18 x - 4 = 0

4 (\frac{5 - 3 y}{2})^{2} - 3 (\frac{5 - 3 y}{2}) y + 9 y^{2} = 15

x^{2} - 4.4 x = - 3.84

z^{2} + 8 = 0

What are the solutions to the equation 3v^2+2v-8=0 ?
The solutions to the equation 3v^2+2v-8=0 are v= 4/3 ,v=-2
Find the zeros of 3v^2+2v-8=0
The zeros of 3v^2+2v-8=0 are v= 4/3 ,v=-2