What are the solutions to the equation (3x+5)(x-3)=5 ?

The solutions to the equation (3x+5)(x-3)=5 are x= 10/3 ,x=-2

Find the zeros of (3x+5)(x-3)=5

The zeros of (3x+5)(x-3)=5 are x= 10/3 ,x=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(3 x + 5) (x - 3) = 5

x = \frac{10}{3}, x = - 2

Decimal Notation

x = 3.33333 \dots, x = - 2

Solution steps

(3 x + 5) (x - 3) = 5

Expand

(3 x + 5) (x - 3) : 3 x^{2} - 4 x - 15

3 x^{2} - 4 x - 15 = 5

Move

5

to the left side

3 x^{2} - 4 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 3 ( - 20 )}{2 \cdot 3}

(- 4)^{2} - 4 \cdot 3 (- 20) = 16

x_{1, 2} = \frac{- ( - 4 ) \pm 16}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 16}{2 \cdot 3}, x_{2} = \frac{- ( - 4 ) - 16}{2 \cdot 3}

x = \frac{- ( - 4 ) + 16}{2 \cdot 3} : \frac{10}{3}

x = \frac{- ( - 4 ) - 16}{2 \cdot 3} : - 2

The solutions to the quadratic equation are:

x = \frac{10}{3}, x = - 2

2 x^{2} + 2 0^{2} b^{2} = 5 ab x

X, X^{2} + y^{2} = 25

x^{2} - 14 + 49 = 0

m^{2} - m - 56 = 0

6 x^{2} - 4 x - 12 = 0

What are the solutions to the equation (3x+5)(x-3)=5 ?
The solutions to the equation (3x+5)(x-3)=5 are x= 10/3 ,x=-2
Find the zeros of (3x+5)(x-3)=5
The zeros of (3x+5)(x-3)=5 are x= 10/3 ,x=-2