What are the solutions to the equation y^2+13=8y ?

The solutions to the equation y^2+13=8y are y=4+sqrt(3),y=4-sqrt(3)

Find the zeros of y^2+13=8y

The zeros of y^2+13=8y are y=4+sqrt(3),y=4-sqrt(3)

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y^{2} + 13 = 8 y

y = 4 + 3, y = 4 - 3

Decimal Notation

y = 5.73205 \dots, y = 2.26794 \dots

Solution steps

y^{2} + 13 = 8 y

Move

8 y

to the left side

y^{2} + 13 - 8 y = 0

Write in the standard form

a x^{2} + b x + c = 0

y^{2} - 8 y + 13 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 13}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 13 = 23

y_{1, 2} = \frac{- ( - 8 ) \pm 2 3}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 8 ) + 2 3}{2 \cdot 1}, y_{2} = \frac{- ( - 8 ) - 2 3}{2 \cdot 1}

y = \frac{- ( - 8 ) + 2 3}{2 \cdot 1} : 4 + 3

y = \frac{- ( - 8 ) - 2 3}{2 \cdot 1} : 4 - 3

The solutions to the quadratic equation are:

y = 4 + 3, y = 4 - 3

9 x^{2} = - 24 x - 10

x, x^{2} + 2 x - 35 = 0

1 = x^{2} + x

1 = x^{2} + 1

4 x^{2} + 48 x + 144 = 0

What are the solutions to the equation y^2+13=8y ?
The solutions to the equation y^2+13=8y are y=4+sqrt(3),y=4-sqrt(3)
Find the zeros of y^2+13=8y
The zeros of y^2+13=8y are y=4+sqrt(3),y=4-sqrt(3)