What are the solutions to the equation 8-2x^2=-3 ?

The solutions to the equation 8-2x^2=-3 are x=sqrt(11/2),x=-sqrt(11/2)

Find the zeros of 8-2x^2=-3

The zeros of 8-2x^2=-3 are x=sqrt(11/2),x=-sqrt(11/2)

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8 - 2 x^{2} = - 3

x = \frac{11}{2}, x = - \frac{11}{2}

Decimal Notation

x = 2.34520 \dots, x = - 2.34520 \dots

Solution steps

8 - 2 x^{2} = - 3

Move

8

to the right side

- 2 x^{2} = - 11

Divide both sides by

- 2

x^{2} = \frac{11}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{11}{2}, x = - \frac{11}{2}

6 x^{2} + 7 x + 7 = 0

x, 2 x^{2} - 3 y^{2} = 5 x y

x^{2} + 19 = 100

120 = x^{2} - 586

x^{2} + 19 = 12 x

What are the solutions to the equation 8-2x^2=-3 ?
The solutions to the equation 8-2x^2=-3 are x=sqrt(11/2),x=-sqrt(11/2)
Find the zeros of 8-2x^2=-3
The zeros of 8-2x^2=-3 are x=sqrt(11/2),x=-sqrt(11/2)