What is (x+2)/(x+4)>(x-3)/(2x-1) ?

The solution to (x+2)/(x+4)>(x-3)/(2x-1) is x 1/2

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(x+2)/(x+4)>(x-3)/(2x-1)

\frac{x + 2}{x + 4} > \frac{x - 3}{2 x - 1}

x < - 4 or x > \frac{1}{2}

Interval Notation

(- \infty, - 4) \cup (\frac{1}{2}, \infty)

Decimal Notation

x < - 4 or x > 0.5

Solution steps

\frac{x + 2}{x + 4} > \frac{x - 3}{2 x - 1}

Rewrite in standard form

\frac{x ^{2} + 2 x + 10}{( x + 4 ) ( 2 x - 1 )} > 0

Identify the intervals

x < - 4 or x > \frac{1}{2}

(8 a^{6} b^{\frac{3}{2}})^{\frac{2}{3}}

12 5^{b} = 5

2 (4 x + 1) = 2 \cdot 4 x + 2 \cdot 1

25 x^{2} - 20 x y + 4 y^{2}

h^{2} + 6 h - 27

What is (x+2)/(x+4)>(x-3)/(2x-1) ?
The solution to (x+2)/(x+4)>(x-3)/(2x-1) is x<-4\lor x> 1/2