What are the solutions to the equation v^2-5v+9=5 ?

The solutions to the equation v^2-5v+9=5 are v=4,v=1

Find the zeros of v^2-5v+9=5

The zeros of v^2-5v+9=5 are v=4,v=1

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v^{2} - 5 v + 9 = 5

v = 4, v = 1

Solution steps

v^{2} - 5 v + 9 = 5

Move

5

to the left side

v^{2} - 5 v + 4 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 4 = 3

v_{1, 2} = \frac{- ( - 5 ) \pm 3}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- ( - 5 ) + 3}{2 \cdot 1}, v_{2} = \frac{- ( - 5 ) - 3}{2 \cdot 1}

v = \frac{- ( - 5 ) + 3}{2 \cdot 1} : 4

v = \frac{- ( - 5 ) - 3}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

v = 4, v = 1

y^{2} - 6 y = - 9

8 - 3 x^{2} = - 22

2 y^{2} = 4

2 y^{2} = 8

2 x^{2} + 5 x + 2 = 0

What are the solutions to the equation v^2-5v+9=5 ?
The solutions to the equation v^2-5v+9=5 are v=4,v=1
Find the zeros of v^2-5v+9=5
The zeros of v^2-5v+9=5 are v=4,v=1